Suppose an angle of 1600 is drawn counterclockwise beginning on the positive x-axis in a standard xy plane....

Question

Where is the final (terminal) side of the angle?? What quadrant??!?!!?

Answer 1

To find this you first determine how many times 360 degrees goes into 1600.  

This gives you 4 times 360 degrees, or four full revolutions with a remainder of 160 degrees, as shown below.

4 x 360 = 1440 degrees

1600 - 1440 = 160.

The 160 degrees is the final angle.  This is in Quadrant II.

Answer 2

The angle 1600 degrees can be taken as 360 + 360 + 360 + 360 + 160. on rotating 360 degrees one returns to the same position.

Hence the total angle will be 160 degrees which is in the 2nd quadrant (between 90 and 180 degrees).

Answer 3

okay if you EVER get anything over 360 degrees. then you must subtract by 360 everytime UNTIL you get an answer from 0 to 360. so the answer is 160 and in quadrant 2 (90-180 degrees).

like the first guy said :)

take care and good luck