Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.070V?

Question

I cannot figure out how to solve this problem. I think I am making it more complicated than it should be. Can someone please help? Please don't give me your opinion, just help me figure out how to solve it. thank you

Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.070V. How much work is done by the electric force when a sodium ion (charge = +e) moves from the outside to the inside

Answer 1

potential is defined as: V = .energy / charge, so:

E = e.V = .07 * 1.6* 10^-19 = 1.12.10^-20 J.

(sodium has charge 1e.)

Answer 2

You need to assume too much, such as the time taken and possibly distance. If it took one second then it would be a simple case of 0.07 x 1/(6.24150948×10^18)...but it's unsure of the time, so it's hard to tell.

Answer 3

Work given by the product of charge and potential difference.

W = (1.60 x 10^-19 C) x 0.070 V = 1.12 x 10^-20 J