Surface area?

Question

The diagram shows a float made from two cones with dimensions as show

http://img231.imageshack.us/img231/1315/79924634op2.jpg

^^^ Picture ^^^^ View it first.

Calculate the total suface area of the float.

Detailed explanation please :)

best answer gets 10 points xD

Answer 1

is this a random question?

Answer:3268866375059886055398863193669...

p.s. the side for the bottom cone is an infinate number.

other solutions:5(square root of 61) pi+ 204.0352248333656050007181991317

you need to make sure that the sides, the heights and the radius make a GOOD right triangle.  here is a checking device: leg one squared plus leg 2 squared = hypotenuse squared.

Answer 2

Given only three points all you can calculate is the area of

the triangle defined by those points.

If this triangle is is on the surface of a sphere then the additional

area in the amount of the 'spherical excess' must  be applied to

determine the area of the spherical triangle.  This is closely

related to the angular 'spherical excess' of triangles on a sphere

IMHO a wonderful teaching device is to draw eight equal spherical

triangles on a sphere.  Each corner of the triangles is 90* hence

the spherical excess is 90*  Sum of angles - 180*

FYI

It can be proven that the sum of the interior angles of a spherical

triangle is always > 180* and < 540*

Spherical Area = pi times r squared times E divided by 180

SA = pi * r**2 * E / 180

where

r = area of sphere

E = Angular Spherical Excess

Top Portion

SA= 3.14 x Rsq x E/180

SA= 3.14 x 10 x 12/180

SA= 3.14 x 100 x .06666

SA= 18.84

Bottom Portion

SA= 9.42

Spherical surface area equals    SA = 28.26 cm