Systems of Equations.....?

Question

work it out for me so i can see how to do it.

I don't care if you include the answer or not, im not a cheater so please feel free to do whatever you like.

here it is:

x - y = 2

3y + 2x = 9

Answer 1

dude that is easy do it yourself

Answer 2

solve for x in the first equation:

x = 2 + y

plug x into the second equation:

3y + 2(2+y) = 9

solve for y:

3y + 4 + 2y = 9

5y = 9 - 4 = 5

y = 5/5 = 1

plug y=1 into either the first or second equation to get x:

x - 1 = 2

x = 2 + 1 = 3

or

3(1) + 2x = 9

2x = 9 - 3 = 6

x = 6/2 = 3

Answer 3

Here, I'll show you.  :D  

First of all, you need to number the top equation and the bottom.  

Eg. 1)  x - y = 2

      2)  3y + 2x = 9

Next, flip number 2 around so that the equation is 2x+3y=9  (You just need to move the 2x and 3y around).  

This is what it looks like right now:  

1)  x - y = 2

2)  2x+3y = 9

Then, you multiply number 1 by two.  

Example :  1)  2x-2y=4

Now, put number 2 below it like so,

1)  2x-2y=4

2)  2x+3y = 9

Subtract them, top to bottom, like an subtraction question.  You should get:  -5y= -5

Bring the 5 on the 'y' side over to the other side (the one with the five) and divide.  

You should get;  y= 1  

That's your first answer, to get x, simply bring 'y' into one of the equations and you'll get 'x' as well.

Like so:  x-1=2  (The 1 is y.)

Turn it around and you'll get:  x=3  

The answers should be x=3, y=1.  

Hope this helped!  :D  

Answer 4

It depends on what methods you are allowed to use.

By the elimination method

multiply the first equation by 3 and align the variables to add the 2 equations together.

3x - 3y = 6

2x + 3y = 9

-------------------

5x      =  15  (the -3y and +3y cancel out)

divide by 5

x = 3

then substitute the value of x into one of the equations to find y

x - y = 2

3 - y = 2

so y = 1

Answer 5

-2(x-y)=2(-2)

-2x+2y=-4

2x+3y=9

+________

     5y=5

     __  _

      5   5

y=1

x-1=2

  +1+1

______

x=3

By the way this took me forever to type up lol

Answer 6

i am assuming you want the point of intersection.

x-y=2

x=2+y

[ x-2=y ]

3y+2x=9

3y= -2x+9

oh do it yourself. it is taking me too long to type it out. do you kind of get the idea from the first one?

Answer 7

First we have to get the equations similar, I'm going to multiply the first equation by 3 to get 3x-3y=6

Then I'm going to take that equation and add it to the second equation

3x-3y = 6

2x+3y=9

5x +0y = 15

x = 3

Then put that back in either equation to find that y = 1

Answer 8

x = 2+y [Sovle for x]

3y + 2(2 + y) = 9  [substitute 2+y for x]

3y + 4 + 2y = 9

4 +5y =9 [solve for y]

5y=5

y = 1  Therefo x = 2 + 1   ...y=1,x=3

Check

x - y = 2          3-1=2        2=2

3y + 2x =9     3(1)+ 2(3) =9      9=9

Answer 9

Two equations and two unknown:

x-y=2 (transpose y to the other side, then)

x=y+2  ----- Equation 1

substitute equation 1 to the second equation (in place of x), therefore

3y+2(y+2)=9    ------ Equation 2

now you only have one unknown, solve for y then substitute to equation 1 to get x.

Answer 10

Using substitution method:

x - y = 2

x = y + 2

Substitute in 2nd equation

3y + 2 (y + 2) = 9

3y + 2y + 4 = 9

5y = 5

y = 1

Solve for x:

x = 1 + 2

x = 3

So x = 3, y=1