Systems of equations? Math help!?

Question

4X = 3 - 6Y

2X - 2Y = 9

THANK YOU!

Answer 1

x= y +9/2 This is the 2nd equation rewritten

then sub this into the 1st

4(y + 9/2) = 3 - 6Y

then u can figure it out from there

Answer 2

4X + 6Y = 3

2X - 2Y = 9

Use process of elimination to solve this system of equation:

Multiply the second equation by -2 and add the result to the first equation:

4X + 6Y = 3

-4X + 4Y = -18

----------------------

10y = -15

y = -3/2

Substitute y = -3/2 into either original equation to solve for x:

4x + 6y = 3

4x + 6(-3/2) = 3

4x -9 = 3

4x = 12

x = 3

Check:

2X - 2Y = 9

2(3) - 2(-3/2) = 9

6 - (-3) = 9

6 + 3 = 9

9 = 9

Therefore,

x = 3, y = -3/2

Answer 3

1st equation ---------->     4x = 3 - 6y

2nd equation ---------->    2x = 9 + 2y (bring -2y to the right side of this equation)

Multiply the 2nd equation by -2, and you get: -4x = -18 - 4y

So,

  

1st equation: 4x = 3 - 6y

2nd equation: -2(2x) = -2(9 + 2y)

So,

4x = 3 - 6y

-4x = -18 - 4y

the x variable cancels out and you get

0 = -15 - 10y

solve for y, which is y = -3/2 or -1.5

plug y back into either the 1st or 2nd equation

so,

1st equation: 4x = 3 - 6(-1.5)

so, x = 3

Answer 4

4x = 3 - 6y

6y = 3 - 4x

y = (3 - 4x)/6

2x - 2y = 9

2y = 2x - 9

y = (2x - 9)/2

Value of x:

2(3 - 4x) = 6(2x - 9)

6 - 8x = 12x - 54

20x = 60

x = 3

Value of y:

= (3 - 4[3])/6

= (3 - 12)/6

= - 9/6 or - 3/2

Answer: x = 3, y = - 3/2

Proof (1st equation):

4(3) = 3 - 6(- 3/2)

12 = 3 + 9

12 = 12

Proof (2nd equation):

2(3) - 2(- 3/2) = 9

6 + 3 = 9

9 = 9

Answer 5

4x + 6y = 3

- 4x + 4y = - 18 -------ADD

10y = - 15

y = - 3/2

2x + 3 = 9

2x = 6

x = 3

x = 3 , y = - 3/2

Answer 6

4x = 3 - 6y

2x - 2y = 9

multiply the second equation by 2 to obtain

4x - 4y = 9

and now you have an equation that says 4x = 3 - 6y, and 4x - 4y = 9, replace the 4x in the second equation with 3 - 6y

so you have

3 - 6y - 4y = 9

now you can solve for y and obtain x from the value of y

hope this helps