Tangential acceleration and normal acceleration

Question

I keep getting this one wrong. Don't understand what is the accele along its path is it tangential accele or the product of tangential and normal???

A particle starts from rest at t=0

It moves along a circular path of radius 13m and has an acceleration along its path of 5.6m/s^2. What is the magnitude of the acceleration when t=5 ?

Answer 1

Acceleration along path is tangential acceleration.

Initial speed u = 0

Tangential acceleration at = 5.6 m/s^2

Let velocity at time t = v

v = u + at * t = 0 + 5.6 * 5 = 28 m/s

Radial acceleration ar = v^2/r = 28^2/13 = 60.3 m/s^2

Magnitude of total acceleration a = sqrt(at^2 + ar^2)

= sqrt(5.6^2 + 60.3^2)

= 60.56 m/s^2