Question:

The amount of potassium permanganate KMnO4 in grams needed to prepare 500 ml 0f 0.4M KMnO4 solution is?

by  |  earlier

0 LIKES UnLike

15.211

31.606

56.921

95.084

 Tags:

   Report
Answer The Question I've Same Question Too

1 ANSWERS

Sort By: Date  |  Rating

  1. The molar mass of KMnO4 is 158 g/mol.

    M = mol of KMnO4 / L of solution

    M = mol / L

    mol = M x L = 0.40 mol / L x 0.500 L = 0.20 mol

    0.20 mol x (158 g / 1 mol ) = 31.6 g KMnO4

You're reading: The amount of potassium permanganate KMnO4 in grams needed to prepare 500 ml 0f 0.4M KMnO4 solution is?

Question Stats

Latest activity: earlier.
This question has 1 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.
Register Now
Unanswered Questions