The average of four numbers is 98. If three numbers are 86,87 and 91, what is the fourth number?

Question

The average of four numbers is 98. If three numbers are 86,87 and 91, what is the fourth number?

Answer 1

4*98= 392

392- (86+87+91) = 128

128

Answer 2

(86+87+91+x )/4 = 98

Solve for x to get x=128

Answer 3

128

because (86+87+91+X) / 4 = 98

98*4= 392

(86+87+91+X)= 392

-86-87-91

X=128

Answer 4

128.

86 plus 87 plus 91 =264

You have to get 98 times 4 which is 392

So you do

392-264, which is 128, which is the answer (the fourth number)

SO it goesL

86+87+91+128 = 392 divided by 4 (the number of numbers there is) which equals 98!

Wola!

hope that helps

Answer 5

128