Question:

The electrostatic force of attraction between charges?

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of +8.0nC and -4.0nC is 2.5 x 10 to the power of -4 N.what is the distance between the charges?

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  1. 9 * 10^9 * 8.0 * 10^(- 9) * 4.0 * 10^(- 9) / r^2 = 2.5 * 10^(- 4)

    r^2 = 9 * 10^9 * 8.0 * 10^(- 9) * 4.0 * 10^(- 9) / [ 2.5 * 10^(- 4) ]

    = (9 * 8 * 4 / 2.5 ) * 10^(- 5)

    = 1.15 * 10^(- 3) m^2

    r = 3.39 * 10^(- 2) m.

    = 3.39 cm.

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