I had a little trouble with this...
Normally, to find the inverse of a function, say, f(x) = 2x-1:
y = 2x -1
And then just switch the domain and range and solve for y, right?
x = 2y - 1
y = (x + 1) / 2
But what if f(x) = 1/x?
By that,
y = 1 / x
x = 1/ y
and solving for y,
You get 1 / x.
So is the inverse of 1/x just 1/x?
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