The largest nugget of gold on record was found in 1872 in New South Wales, Australia, and had a mass of 93.3 k

Question

The largest nugget of gold on record was found in 1872 in New South Wales, Australia, and had a mass of 93.3 kg.

(a) Assuming the nugget is pure gold, what is its volume in cubic centimeters?

(b) What is it worth by today’s standards if gold is $345/oz? (14.58 troy oz = 1 lb)

Answer 1

density of gold is 19.30 g/ml

the nugget is 93.3kg or 93300g

so volume is 93300g / 19.30 g/ml = 4834 ml or cm³

93.3kg is 3000 troy oz, at $345/oz = $1,035,000

(Actually gold is close to $1000/oz now, which is $3M)