The manager of at Cream of the crop bought a load of watermelons for $200. ?

Question

The manager of at Cream of the crop bought a load of watermelons for $200. She priced the melons so that she would make $1.50 profit on each melon. When all but 30 had been sold, the manager had recovered her initial investment. How many did she buy originally?

Please provide answer ASAP

The chapter I am studying is Quadratic Equations and Inequalities this is one of the word problems, I manage to answer all but this one, I am stump please HELP!

Answer 1

idk how your teacher wants you to solve this, but here is the simplest way i can think of.

Let x = the amount of water melons bought

Let x-30= the amount of water melons sold

let c+ 1.50= the selling price where c is = to the price without profit

so we have (x-30) * (c +1.5) = $200

since the amount sold * the total selling price = her original invest ment

c * x = 200$

We get this formula because the non profit price(the price she bought it for) multiplied by the amount bought = 200$ (her investment)

From here we make equalities since they both = 200$

(x-30)(c+1.5) =200

c*x=200

to obtain one variable we just substitue since all variables int his equation pertain to the same thing.

c=200/x

(x-30)(200/x +1.5)=200

200 + 1.5x - 6000(this was my error i put 600)/x - 45 = 200

155 + 1.5x - 6000/x = 200

multiply both sides by x

155x + 1.5x^2 - 6000 =200x

to get rid of decimals times both sidse by 10

1550x + 15x^2 - 60000= 2000x

15x^2 -  450x - 60000 = 0

15(x^2 - 30x - 4000)= 0

15(x -80) (x+50)=0

x=80 or x=-50, but it has to be positive so its 80

so 80 water melons bought

50 water melons sold

c*x=200 so c(80)=200 so c=2.50

original price bought for = $2.50

This is right since if 50 of them sold (80-30) at 4.00 each (2.50 +1.50 profit) then taht would = 200$

still trying to figure out what i did wrong (fixed it now)

Answer 2

The manager of at Cream of the crop bought a load of watermelons for $200. She priced the melons so that she would make $1.50 profit on each melon. When all but 30 had been sold, the manager had recovered her initial investment. How many did she buy originally?

maconjoa... here it is:

Let M = number of Watermelons sold

Load of watermelon = $ 200. 00

The number of watermelon sold => $ 1.50 /melon  x  M (melon)  = $ 200.00

=> M = $ 200.00 / $ 1.50

=> M = 133. 33 ← but there is no 0.33 melon

so => M = 133 melons

The number of melon in a the load = 133 + 30

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Ans::The number of melon in a the load = 163  watermelons

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hope this helps

Answer 3

Suppose n. then n-30 were sold and 1.5(n-30) = 200 solve it.

But there is NO quad eqn in this.

Pl check evrything. Is it from the same chapter you are studying and the problem itself. See 2000 is not divisible by 3 so the answer to this will be in fraction not Integer.

It seems strange to me that some one buys melons in fraction.