The pH of acetic acid is 3.26. What is the concentration of acetic acid and what is the percent acid ionized?

Question

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Answer 1

the Ka for acetic acid is 1.75 X 10^-5  so Ka = [H+][OAc]/[ HOAc]

1.75 X 10^-5 = [X][X]/C-X

a small amount of the acetic acid ( X ) of concentration C will ionize to give that same amount of  H+ and of Aco^-1

since the pH is 3.26 the [H+] is the antilog of that ...5.5 X 10^-4

so C = (5.5 X 10^-4)( 5.5 X 10^-4 )/1.75 X 10^-5   C = 1.728 X 10^-2 M

=0.0172 M  the percent ionized is 5.5 X 10^-4 /1.72 X 10^-2  X 100

3.18 X 10^-2  X 100 = 0.318 %