The phenotypic ratio resulting from a dihybird cross showing independent assortment is expected to be what?

Question

The phenotypic ratio resulting from a dihybird cross showing independent assortment is expected to be what?

Answer 1

Phenotype: 9:3:3:1

Consider a cross between a Round & Yellow pea seed(RRYY) with Wrinkled & Green one(rryy)

The result will be

9 Round & Yellow [1-RRYY, 2-RRYy, 2-RrYY, 4-RrYy

3 Round & green  [1-RRyy, 2-Rryy]

3 Wrinkled & Yellow [1-rrYY, 2-rrYy]

1Wrinkled & green [1-rryy]

Answer 2

This question is unanswerable because you haven't provided us with the genotypes being crossed (or information from which we can determine the genotypes).  

Dihybrid just means you're looking at two genes at once.  But, the parents could be AABB x AABB or AaBb x aabb, etc.  Each cross would give different ratios.  So, we need more information to provide an answer.