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The radius of a circle was doubled.express the area of th orginal circle as a ratio of the new one?

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The radius of a circle was doubled.express the area of th orginal circle as a ratio of the new one?

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  1. area of original circle= pi r^2 =x(let)

    area of new circle= pi (2r)^2 = pi 4 r^2

    => area of new circle = 4x

    therefore,  area of original circle : area of new circle = x/4x = 1 : 4

    or area of aorginal circle= 1/4 times area of new circle


  2. the ratio is 1:4

    the area of original circle is pi.r.r

    the area of new circle is pi.2r.2r

    so the ratio is 1:4

  3. ratio= 1:4

    as area of original cirlce=pi r^2

    area of new circle= pi (2r)^2

    if you divide one by the other u get 1/4

  4. area = pi r^2

    area1 =  pi r ^ 2

    area2 = pi (2r) ^ 2 = pi 4 r^2

    area1/ area2 = (pi r ^ 2) / (pi 4 r^2) = 1/4  or 1:4

  5. Circle 1

    ----------

    radius = r

    A1 = π r ²

    Circle 2

    -----------

    A2 = π (2r)²

    A2 = 4 π r²

    A1 : A2 = 1 : 4

  6. WHEN THE RADIUS IS DOUBLED,AREA BECOMES 4 TIMES THE ORIGINAL ONE.

    THE RATIO IS 1:4.

  7. original:new

    1:2

  8. Let r be the original radius. Original area = πr²

    If the radius is doubled, then the area of the new circle is =  ÃÂ€(2r)² = 4πr²

    So the ratio for area of old circle : new circle = πr² : 4πr² = 1: 4

    AJM

      

  9. 1:4

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