The reaction of 11.9 g of CHCl3 with excess chlorine produced 12.6 g of CCl4, carbon tetrachioride:?

Question

what is the percent yield?

2CHCl3 +2Cl2 ----> 2CCl4 +2HCl

Answer 1

Moles CHCl3 = 11.9 g / 119.378 g/mol = 0.0997

the ratio between CHCl3 and CCl4 is 2 : 2

moles CCl4 = 0.0997 => 0.0997 mol x 153.823 g/mol =15.3 g ( theoretical yield)

% yield = actual yield x 100 / theoretical yield = 12.6 x 100 / 15.3 = 82.3 %