Question:

The resistors Ra and Rb are connected in series across a 120 volt source.?

by Guest60503  |  earlier

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The resistors Ra and Rb are connected in series across a 120 volt source. When a 30,000 ohms voltmeter is connected across Ra and then across Rb, the instrument deflection is 48 volts in each case. What are the values of the resistors?

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  1. The resistors are equal, and each has 60 volts across it with the meter missing.

    It = total current with meter connected

    Im = current through meter

    Im = 48/30k = 1.6ma

    It = 72v/R (unbridged R)

    R = 72/It

    R = 48/(It-1.6ma) (R with meter)

    72/It = 48/(It-1.6ma)

    72*(It-1.6ma) = 48*It

    72It - 115.2m = 48*It

    24It = 115.2m

    It = 4.8 ma

    R = 72/4.8 = 15k

    check

    15k parallel 30k = 10k

    total I, with meter = 120/(15k+10k) = 4.8ma

    drop across 10k = 48v

    .


  2. first of all u can say the resistors are identical because the voltmeter deflection is the same for both.

    2nd, u know when connected in series, the ratio of voltages of resistors is equal to the ratio of their values of resistance. (V2/V1=R2/R1).

    and 3rd, u know when connected in parallel, the equivalent resistance is R1R2/(R1+R2).

    now u have this equation: 48/(30000R/(R+30000))=72/R.

    solving for R yields: R = 15000 Ohms ans

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