The specific heat of water is 4.2 kj/kg. C. When 400 kj of heat is added to 12 kg of water at 2 C, its final?

Question

temp is?

a. 5.9 C

b. 7.9 C

c. 11.7 C

d. 17.9 C

Answer 1

Specific heat capacity is given by Q = mc∆T. Solve for the change in temperature.

∆T = Q / mc = 400,000 J / (12 kg x 4,200 J/kg) = 7.9°C

Tf = ∆T + Ti = 7.9°C + 2.0°C = 9.9°C