Question:

The speed of a synchronous motor with 60 Hz.power supply is

by Guest62814  |  earlier

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100rpm,600rpm,3600rpm,4000rpm

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  1. Speed = 60 x Frequency ÷ (Poles ÷ 2)

    Speed is measured in RPM's

    Frequency = 60 Hz.

    Poles = Number of poles in the motor windings.

    Simplifying the equation, RPM = (120 x Frequency) ÷ Poles

    RPM = (120 x 60) ÷ Poles

    RPM = 7200 ÷ Poles

    Poles come in pairs -- north and south.  The smallest number of poles in a motor is 2.  Adding more sets of poles to the motor windings reduces the speed of the motor.

    Ultimately the speed of a synchronous motor operating at 60 Hz will always be a multiple of 60.


  2. Speed N= 120f/p

    In your question, there is no number of poles, so the only probability is 2 poles, in which case N= 120(60)/2 =3600rpm.

  3. Depends how many poles it has..speed=(120*F)/P where f in frequency and p is the number of poles...



  4. Speed (RPM) = 120 x f / p

    f = frequency

    p = number of poles.

    2 poles, speed = 3600 RPM

    4 poles, speed = 1800 RPM

    .

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