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The sum of 2 digit number is equal to difference between them. find how many such numbers are possible?

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The sum of 2 digit number is equal to difference between them. find how many such numbers are possible?

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  1. The number xy,

    then x+y = x-y

    or x+y = y-x

    Either way, one of them must be 0,

    and since it is specified that

    they form a two-digit number,

    it must be the second one.

    They are then 10, 20, 30, ..., 90

    .


  2. there are 9 such numbers.
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