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The sum of 2 digit number is equal to twice the difference between them. find how many such nums are possible?

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The sum of 2 digit number is equal to twice the difference between them. find how many such nums are possible?

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  1. hi

    (x+y)=2(x-y) ==> x=3y ==>

      it's a line with infinitepoint

    then there are infinite numbers  


  2. x+y =2(x-y)

    x+y =2x-2y

    3y =x

    Since it is not specified which digit the tens or the unit is larger, you can have:

    13, 31, 26, 62, 39, 93

    6 numbers
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