Question:

The sum of cubez!! plz help!! will give 10 points!! Thankz!!!?

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The Sum and Difference of Cubes

The ^ stands for exponente

Please complete the following exercises

1.) 64^3+1

2.) 1-125b^3

3.) 8x^3y^6+27

4.) a^3b^6-b^3 (Remember to take out the GCF)

5.) 27x^3-8y^3

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  1. the formulae  for solvin' the following problems are:

    a^3+b^3=(a+b)(a^2+b^2-ab)

    a^3-b^3=(a-b)(a^2+b^2+ab)

    1.) 64^3+1

    (64+1){64^2+1^2-64*1}

    =65(4033)

    =262145

    2.) 1-125b^3

    =1-(5b)^3

    (1-5b)(1+25b^2+5)

    3.) 8x^3y^6+27

    =(2xy^2)^3+3^3

    =(2xy^2+3){(2xy^2)^2+3^2-2xy^2*3}

    =(2xy^2+3){4x^2y^4+9-6xy^2}

    4.) a^3b^6-b^3

    b^3(a^3-1)

    =b^3(a-1)(a^2+1-a)

    5.) 27x^3-8y^3

    (3x)^3-(2y)^3

    =(3x-2y)(9x^2+4y^2+6xy)

    Please rate me ::))


  2. a^3 + b^3 = (a + b)(a^2 - ab + b^2)

    a^3 - b^3 = (a - b)(a^2 + ab + b^2)

    1)

    64^3 + 1

    = 64^3 + 1^3

    = (64 + 1)(64^2 - 64 + 1^2)

    = (65)(4096 - 64 + 1)

    = (65)(4033)

    = 262145

    2)

    1 - 125b^3

    = 1^3 - 125b^3

    = (1 - 5b)(1 + 5b + 25b^2)

    3)

    8x^3y^6 + 27

    = 2^3x^3(y^2)^3 + 3^3

    = (2xy^2 + 3)(4x^2y^4 - 6xy^2 + 9)

    4)

    a^3b^6 - b^3

    = (ab^2 - b)(a^2b^4 + ab^3 + b^2)

    = b(ab - 1)(a^2b^4 + ab^3 + b^2)

    = b^3(ab - 1)(a^2b^2 + ab + 1)

    5)

    27x^3 - 8y^3

    = (3x - 2y)(9x^2 + 6xy + 4y^2)

  3. Sum of Cubes:

    a^3 + b^3 = (a + b)(a^2 - ab + b^2)

    Difference of Cubes:

    a^3 - b^3 = (a - b)(a^2 + ab + b^2)

    1)

    64^3 + 1

    = 64^3 + 1^3

    = (64 + 1)(64^2 - (64)(1) + 1^2)

    = (65)(4096 - 64 + 1)

    = (65)(4033)

    = 262145

    2)

    1 - 125b^3

    = 1^3 - 5^3 b^3

    = 1^3 - (5b)^3

    = (1 - 5b)(1^2 + 1(5b) + (5b)^2)

    = (1 - 5b)(1 + 5b + 25^2)

    3)

    8x^3y^6 + 27

    = 2^3 x^3 y^6 + 3^3

    = (2xy^2)^3 + 3^3

    = (2xy^2 + 3)[(2xy^2)^2 - (2xy^2)(3) + 3^2]

    = (2xy^2 + 3)(4x^2y^4 - 6xy^2 + 9)

    4)

    a^3b^6 - b^3

    = (b^3)(a^3 b^3 - 1)

    = (b^3)[(ab)^3 - 1^3]

    = (b^3)(ab - 1)(a^2b^2 + ab + 1)

    5)

    27x^3 - 8y^3

    = (3x)^3 - (2y)^3

    I think you can finish this one yourself now.

  4. 1) (64 + 1)(64^2 - 64 + 1) = 65 x (4096 - 64 +1)

    2) (1 - 5)(1 + 5 + 5^2)= (-4)x31 = -124

    3) (2xy^2+3)(4x^2y^4 - 6xy^2 + 9)

    4) b^3(a^3b^3-1) = b^3(ab-1)(a^2b^2+ab+1)

    5) (3x-2y)(9x^2 + 6xy + 4y^2)

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