The sum of three consecutive numbers is600. what is the least of these three numbers?

Question

please answer it where an 11 year old can understand

Answer 1

199, 200, 201. :) The lowest one is 199. You can calculate this by saying that 200 times 3 would be 600, therefore one less than 200 plus 200 plus one more than 200 would be 600. Hope this helps!

Answer 2

x + (x + 1) + (x + 2) = 600

3x + 3 = 600

3x = 597

x = 199

Numbers are 199 , 200 , 201

Answer 3

let the three unknown consecutive numbers be x, y and z

x + y + z = 600 [all numbers sum to 600]

y = x + 1 [if x,y,z are consecutive then y = x+1]

z = y + 1 = x + 2 [if x,y,z are consecutive then z = y + 1 = x + 2]

Substitute for y and z in the first equation using the second and third equations:

x + (x+1) + (x+2) = 600

x + x + 1 + x + 2 = 600

3x + 3 = 600

3x = 597

x=597/3 = 199

The three numbers are 199, 200, and 201 with 199 being the least.

Answer 4

199

Answer 5

Since they are consecutive numbers the three numbers are of the form:

x, x + 1, x + 2

Therefore,

Adding these all together:

x + (x + 1) + (x + 2) =  600

Now solving, for x:

3x + 3 = 600

3x = 597

x = 199

Hope this helps!

Answer 6

600/ 3 = 200 or average of 200

199, 200, 201

199 is the number with the least value.

Answer 7

199.

      199

      200

   + 201

   -------

      600