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The sum of two numbers is 55. four times the smaller is 5 less than the larger.find the numbers?

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The sum of two numbers is 55. four times the smaller is 5 less than the larger.find the numbers?

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  1. x + y = 55

    4x = y - 5 ==> y = 4x + 5

    x + (4x + 5) = 55

    5x = 50

    x = 10

    y = 4x + 5 = 45


  2. x + y = 55

    4x = y - 5

    5x = 50

    x = 10

    y = 45

  3. Let the smaller be x, then the larger is 55-x.

    4x = (55-x) - 5 = 50-x

    5x=50

    x=10

    55-x=45


  4. let the smaller no. be x, and the larger no. be y

    x + y = 55 --- (1)

    4x = y-5 --- (2)

    (2)/4: x = (y-5)/4 --- (3)

    sub (3)into (1):(y-5)/4 +y = 55

    (y-5+4y)/4 = 55

    (5y-5)= 55 * 4

            = 220

    5y = 225

    ~ y = 45

    ~ x = 55 - 45

       =10


  5. 45 and 10

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