Question:

The volume occupied by 2.25 moles of CH4 gas at STP is what in L?

by Guest63813  |  earlier

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The volume occupied by 2.25 moles of CH4 gas at STP is what in L?

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  1. The easiest way to do this type of problem is to remember that "1mole of any gas at STP has a volume of 22.4 litres"

    You have 2.25 moles of CH4

    Therefore, volume = 2.25*22.4 = 50.4 litres.

    PS If you are what your name says you are: Good luck with your studies - you are to be admired!!


  2. 1 mole of any gas occupies 22.4 liters at STP.  Multiply that number by the number of moles you have and that will tell you how many liters.

  3. 1 mole of CH4 = 22.4 lt

    2.25 mole of CH4 = 22.4*2.25

                              =50.4 litres

  4. At STP, one mole of CH4 gas will occupy 22.4L according to Avogadro's law. Therefore, 2.25 moles will occupy 22.4 x 2.25 Litres = 50.4 Litres.

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