There are 3 males and 2 females,find the possible no of orders that can be made?

Question

the arrangement is between two males one women is allowed to sit.

Answer 1

m1f1m2f2m3      m1f2m2f1m3

m1f1m3f2m2      m1f2m3f1m2  

m2f1m1f2m3      m2f2m1f1m3

m2f1m3f2m1      m2f2m3f1m1

m3f1m1f2m2      m3f2m1f1m2

m3f1m2f2m1      m3f2m2f1m1

so there are 12 possibilities

Answer 2

Hun, for all these type of questions, just multiply them, in no particular order.  Say it's 3 red shirts, 2 blue shorts, 2 yellow shoes.  How many possible sets can be made?  3*2=6*2=12.  Therefore, 12 possible sets.

And yes, the answer would be 6.

Answer 3

3! * 2! = 12

Answer 4

AS IT IS COMBINATION

THREE MEN CAN BE ARRANGE  WITH TWO SELECTION

3| / 2| =6/2=3

ONE WOMAN OUT OF TWO CAN BE SELECTED   =2| / 1| =2

TOTAL OPTION WILL BE 3 X 2 = 6

M1 M2 F1

M1 M2 F2

M2 M3 F1

M2 M3 F2

M1 M3 F1

M1 M3 F2

Answer 5

Let a,b,c be male and p,q are female. Then the possible pairs are:

(a,b,p)

(a,b,q)

(a,c,p)

(a,c,q)

(b,c,p)

(b,c,q)

Hence six pairs, assuming that (a,p,b) is equivalent to (b,p,a) are possible.

If both are different then 12 pairs are possible by getting the other six pairs just by reversing the order.

AJM

Answer 6

First arrange males. it can be done in 3! ways = 6ways

Now, there are 4 gaps. Arrange 2 females in 4 gaps; it can be done in 4P2 ways=12 ways

Hence, total number of ways=6x12=72

Answer 7

2+2+3

Answer 8

12