Thermal energy Q's?

Question

A 17 kg child slides down a 2.9 meters -high playground slide. She starts from rest, and her speed at the bottom is 2.1 m/s.

What is the change in the thermal energy of the slide and the seat of her pants? In joules

Answer 1

Energy Conservation :-

G.P.E = K.E + ∆Q

mgh = ½mV² + ∆Q

(17)(9.81)(2.9) = ½(17)(2.1)² + ∆Q

∆Q = 446.148 J ≈ 450 J