This is for a genius?

Question

find the ortogonal trajectory

1.y^2=x^3/(2a-x)

2.(x^2+y^2)^2=(x^2-y^2)a^2

solve

1.p^3+4xyp+8y^2=0 where p=dy/dx

(this is an eqn solvable for x)

Answer 1

p^3+4xyp+8y^2=0 where p=dy/dx

-p^3 - 8y^2= 4xyp

-p^3 - 8y^2 / 4yp= x

-p^3/4yp    - 8y^2 / 4yp = x

-p^2/4y  - 2y / p = x

I don't know what your talking about on the first eq.

Answer 2

Eleventy-leven!

Answer 3

Niner...