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Three Identical 6.40kg masses are hung by three identical springs. Each spring has a force constant of

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7.80kN/m and was 12 cm long before any masses were attached to it. How long is each spring?

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  1. If x is the extension of each spring:

    6.40 * 9.81 = 7.80 * 10^3 x

    x = 8.05 * 10^(- 3) metres.

    The length of each spring is therefore:

    0.12 + 0.00805

    = 0.128 m. to 3sf.

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