Three men rented a room in a hotel for $30, each paying $10. the manager discovered that they had been over-?

Question

charged and sent the bellboy to return $5. the dishonest bellboy could not see a way of sharing $5 between three people so he returned $1 to each man and kept $2 himself. Thus, each man paid $9, or $27 in totol, and the bellboy kept $2, totalling $29. where is the missing dollar?

- Explain the problem

- Explain your working out

- State answer

-Good luck and see if you can do this.

Answer 1

the manager has it, 5 from 30 is 25, 3 goes to the men and the bellboy keeps 2, if the manager had given him 6 then all would be equal

Answer 2

IN MY POCKET!

Answer 3

lol what are 3 men staying in a hotel room for?

Answer 4

once the men had been overcharged...their total was $25...split three ways...so each man payed $8.33.

once the bellboy came around...each man payed $9.33, not $9.

$9.33 * 3 = $28...plus the bellboys $2

Answer 5

each guy pays 10$, so that's thirty then the 5 dollars is returned

so it was just added up to be confusing

b/c there's the 5$ that was returned

after the 30

that would make it 25$ plus the 5$ returned equals 30

???

I don't really know, that's just my guess

:)

Answer 6

30-5=25 +3 (1 dollar each) = 28 + 2 (bellboy) = 30

Answer 7

"Thus, each man paid $9, or $27 in totol, and the bellboy kept $2, totalling $29. where is the missing dollar?"

The key question come from the above sentence.

Before start to calculate, we should be clarify the following:

1. Did the 3 men pay $35 or $30 in total in the first place? If assuming that they pay $30, then the Manager must be giving them special discount of $5.

2. Then the total they pay should be $30-$5=$25.

3. $25 + 3 = $28

4. Bell Boy $2

5. $28+$2= S$30.

Nothing wrong with the account. NO MISSING of $1

Answer 8

I always liked this riddle (or whatever you want to call it), but it's hard to explain.

The way they describe it just doesn't work because each man paid $9, but the bellhop kept $2.  So that's $27 - 2 = $25.  The bellboy has $2, the manager has $25, and the men each have $1 left over, which totals $30.

When you say that they each paid $9 and the bellboy has $2, you're accounting for that $2 dollars twice because he took the $2 out of the $27 or $9 apiece.  All of the money has been accounted for.  Again, the $2 that the bellboy has came from the $9 apiece, because even if they'd just paid $9 originally, there'd still be two dollars left over.  So it should be thought of as them each paying $9, the bellboy keeping $2, and them keeping their 10th dollar each...the riddle is just a cute way of confusing people :-D

Answer 9

There are actually 2 missing dollars, and the bellboy (or bellhop, as I call them) has both of them.

The problem is that you can't add the two dollars to the total. The bellhop didn't add two dollars, because those two dollars are already part of the nine dollars the men paid. So the total is only $27.

And the reason the total is $27 and not $30 is that the bellhop gave back the three dollars the men paid at first. So you can't count them again and still say that the men paid $9 each.