Ticker tape question?

Question

this type of question has been bothering my for years

on the question paper, i have a tap.

an object falls which pulls the tape through the time ticker

the distance between the first and second dot is 1.6cm.

the ticker tape timer prints dots on a tape every 1/50 secs.

what is the velocity of the object?

ans is 80m/s but i don't know w=how to get it

Answer 1

Easy. The distance between two dots is 1.6 cm. It takes the machine 1/50th of a second to cross this distance. The length crossed per second is 1.6×50 = 80 cm/second.

So the answer is actually 80 cm/s, not 80 m. That would be extremely rapid.