Tin (IV) chloride is produced in 82.2% yield by the reaction of tin with chlorine. How much tin is required?

Question

Tin (IV) chloride is produced in 82.2% yield by the reaction of tin with chlorine. How much tin is required?

Answer 1

This is a bookkeeping question.  You need to tell us how much tin(IV) chloride you want to make.

Otherwise it's a little bit like asking how much money I need to buy bananas if I don't tell you what weight of bananas I want to buy.

Answer 2

I answered a question similar to yours, 7 hours ago, that person said:

Help me in Stoichiometry quiz tomorrow thankz?

help me please to solve this problem..thanks

1.) Tin(IV) chloride is produced in 82.2% yield by the reaction of tin witch chlorine. How much tin is required to produce a kilogram of Tin(IV) chloride.?

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& I answered with:

the % yield requires you to increase the amount of Sn required to produce 1 Kg of SnCl4, not decrease the Sn

using molar masses:

? grams Sn = 1000g SnCl4 @ 118.7 g/mol Sn / 260.50 g/mol SnCl4 =

455.66 g of Sn is required when there is 100 % yield of SnCL4

@ 82.2 % yield,... you need more Sn to be added to yield 1 Kg :

455.656 g @ 100% / 82.2% = 554 grams of Sn

that's your answer: 554 grams of Sn , (aka 0.554 kg)