Titration of KHP and NaOH

Question

Standardization of sodium hydroxide solutions is often accomplished by titrating potassium hydrogen phthalate (KHC8H4O4), also known as KHP, with NaOH solution to be standardized.

The titration of 0.5512g of KHP required 25.92mL of an NaOH solution to reach the equivalence point. What is the concentration of the NaOH solution?

Any help would be appreciated.

Answer 1

Jo....at equivalence point or your estimate of the EP which is called endpoint was the volume of NaOH you used to cause the first permanent pink of the phenolphtahlein indicator. At this point , with only slight error ,the meqs of the base = meq of the acid

so meq = (vol )(N) of base   and meq = wt /meq weight acid

KHPH is a monoprotic acid so its meq weight = mformula weight

a millifromula weight of KHPH will provide one meq of H+   s****.>
204.2 = formula weight  0.2042 = mformula weight

Vol NaOH ( NNaOH ) = 0.5512/0.2042

= 0.5512grams/0.2042 grams/meq x 25.92 mL  = 0.104 meq/mL = 0.104 M

so N( M ) NaOH = 0.104 M  

Answer 2

Ok...forget bout the K and the Na because they are both neutral. set up an equation adding OH to HP which will yield P and H2O. Then set up an ice table in moles to get your equilibrium point moles. Then divide the mols of the OH solution by the total liters and you'll get your final concentration.  

Answer 3

all i member is i think its a 1:1 RATIO