Torque on a wire loop?

Question

A 1.67 m long wire carrying a current of 1.87 A forms a 3-turn loop in the shape of an equilateral triangle. If the loop is placed in a constant uniform magnetic field with a magnitude of 0.735 T, determine the maximum torque that acts on it.

I think I am doing it right but my answer isnt working. I am using the formula NBIA=max torque.

Answer 1

Finding the area requires the use of the formula for the area of a triangle, which is one-half base times height. Since the long wire forms an three equilateral triangles, divide by nine to obtain the length of one side of one of the triangles.

b = 1.67 m / 9 = 0.186 m

Using the Pythagorean theorem, the height is:

h = ((0.186 m)² - (0.186 m / 2)²)^(1/2) = 0.161 m

The area is:

A = ½bh = 0.5 x 0.186 m x 0.161 m = 0.015 m²

The torque is:

τ = NIAB = 3 turns x 1.87 A x 0.015 m² x 0.735 T

= 6.19 x 10^-2 N·m