Trains A and B are traveling in the same direction on parallelo tracks. Train A is traveling at 100 miles.?

Question

Trains A and B are traveling in the same direction on Parallel tracks. Train A is traveling at 100 miles per hour, and train B is traveling at 104 miles per hour. Train

A passes a station at 5:10 p.m. If train B passes the same station at 5:40 p.m., at what time will train B catch up to Train A?

Answer 1

Train B will take 12.5 hours to catch up with train A. That makes it 6.10am the following day.

Train A has a lead of 50 miles on train B. Train B is gaining on train A at 4 mph, so to close the lead will take the time it takes to travel 50 miles at 4mph, i.e. 12.5 hours.

Answer 2

nobody rides the train anymore....

Answer 3

When train A stops. I don't know. I was never good in math.

Answer 4

If 'A' passes the station at 5.10 pm and 'B', 30 minutes later, then it is 52 miles behind. (it covers 104 miles every hour - if it passes the station 30 minutes later then it must be 52 miles behind)

By the time it gets to the station it is only 50 miles behind 'A'. 'B' covers 4 miles further per hour than 'A', so it will take 50/4 = 12 1/2 hours to catch 'A'. therefore it will catch 'A' at 6.10 am.

Answer 5

When train A stops. lol

Answer 6

At 610 am  train b is moving 4 mph faster than  train a. A has a 50 mile lead when train b goes by the station.  50 miles divided by 4 =12.5 hours. Your going to need a lot of track in front of you  lol

Answer 7

The problem is that both trains will have to stop before B catches A in order to change crews;  train & engine crews can only work 12 hours total under the hours of service.

In reality, the question is moot.