Question:

Tricky math question ?????????????

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Mr. Newton drives to and from work over the same route each day. On Friday, he drives at an average rate of 52 km/hr and is one minute late to work. On Monday, he drives at an average rate of 60 km/hr and is one minute early to work. If he left home at the same time each day, what is the distance Mr. Newton travels from home (one way) to work?

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  1. d = 52(t+1)/60 = 60(t-1)/60

    52t + 52 = 60t - 60

    t(60 - 52) = 60 + 52

    8t = 112

    t = 112/8 = 14

    d = 60(14 - 1)/60 = 13 km


  2. i think u need help on ur homework....

  3. 13km

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