Trigonometry problem?

Question

Prove that

cosec^2a-cos^2a/cot^2a=sec^2a

Answer 1

It is coming to sec^2a - sin^2a

I think the question is wrong.

Answer 2

just leave it hahahahahaha

Answer 3

This one is a mater of knowing your definitions

cosec = 1/sin

sec = 1/cos

cot = 1/tan

tan = sin/cos

putting all this together you get

cosec^2a = 1/sin^2a

cot^2a = cos^2a/sin^2a

so we have

1/sin^2a - sin^2a = (1 - sin^4a)/sin^2a

Using cos^2a + sin^2a = 1 this becomes

cos^2a/sin^2a = cot^2a

So I don't get your answer, I just get cot^2a not sec^2a

Answer 4

I had tried but didn't get dat. U r wrong somewhere.Get it rectified.

Answer 5

the answer is cot^2a but not sec^2a.i think your wrong somewhere

Answer 6

= (1/sin^2a - cos^2a) / cot^2a  

= [(1 - cos^2a sin^2a) / sin^2a]  /  (cos^2a/ sin^2a )

= (1 - cos^2a sin^2a) / cos^2a

= 1/cos^2a - (cos^2a sin^2a) / cos^2a

=sec^2a - sin^2a

There's something very wrong with the question !

Because at the end  it comes "sec^2a - sin^2a"  instead of "sec^2a"

Answer 7

I Think there is some mistake in the question.

rewrite the question in words.

Answer 8

1/sin^2(a) + cos^2(a)/ [cos^2(a) /sin^2(a)]

=1/sin^2(a) +sin^2(a)

=(1+sin^4(a)) /sin^2(a)

Are you sure this question is correct or did you forget the ( ) in the numerator?