Uniform rod: m=10kg, l=1m is pinned to the ground at 45 degrees and released. Velocity at horizontal?

Question

Uniform rod: m=10kg, l=1m is pinned to the ground at 45 degrees and released. Velocity at horizontal?

Answer 1

use conservation of energy

energy at beginning = energy when it hits ground

m g h = 1/2 m v^2

g h = 1/2 v^2

v = sqrt(2gh)

plug this into v, h = l sin 45 m/s and  g = 9.8m/s^2