Question:

Use Linear Approximation to approximate the cube root of 125.2?

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Let f(x)= cube root of x. The linear approximation to f(x) at x=125 can be written in the form of y=mx+b, where m is ? and b is ?

Please help me find "m" and "b"

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  1. 125 = 5^3

    therefor, the cube root for 125  is 5.

    f(x) = x ^ (1/3)

    from what i can deduct, m can only be obtained depending on x.

    and you have:

    mx+b = x ^ (1/3)

    so b=0    and

         mx = x ^ (1/3)

    which means that m = [x ^ (1/3) ] / x = x^[ (1/3) - 1] = x ^ ( -2/3).

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