Use algebra to calculate where 4x-3y=11 and 5x-6y=9 intersect.?

Question

Thanks!

Answer 1

- 8x + 6y = - 22

5x - 6y = 9-----ADD

- 3x = - 13

x = 13 / 3

52/3 - 3y = 11

3y = 19 / 3

y = 19 / 9

x = 13 / 3 , y = 19 / 9

Answer 2

4x-3y=11 (Multiply equation by -2 )

-8x + 6y = -22

5x  - 6y  =  9

----------------------------- Add straight down

-3x = -13

x = 13/3

solve for y

4*13/3 - 3y = 11

52/3 - 3y = 11 (Subtract 17.33333 from both sides)

- 3y = -6.333333

y = 2.1111111  or 19/9

Solution : (13/3 , 19/9) is the point of intersection

Good luck to you !