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Use the integration by parts to find the integral. INT x(x+1)^8 dx ?

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Use the integration by parts to find the integral.

INT x(x+1)^8 dx

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  1. u=x

    du=1dx

    dv=(x+1)^8

    v=(1/9)(x+1)^9

    ∫x(x+1)^8dx

    =(1/9)x(x+1)^9-(1/9)∫(x+1)^9dx

    =(1/9)x(x+1)^9-(1/9)(1/10)(x+1)^10

    You can simplify that if you want.

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