Question:

Use the quadratic equation to solve the problemx^2-5x=-9?

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use the quadratic equation to solve the problem

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  1. if the quadratic equation is     x = -b +or- square root b squared minus 4ac all over 2a (a is the coeffcent of x^2 etc) then the equation equals to  

    x = 5 +and- i square root of 11 / 2 (5 +and- square root of -11/5)


  2. Put it into standard form:

    x^2 - 5x + 9 = 0

    In this case, a = 1, b = -5 and c = 9.  The Quadratic Formula is

    x = (-b +/- sqrt(b^2 - 4ac))/2a

    = (-(-5) +/- sqrt((-5)^2 - 4(1)(9)))/2(1)

    = (5 +/- sqrt(25 - 36))/2

    = (5 +/- 3i)/2

    where i is the imaginary, the square root of -1.

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