U²-22U-48? I cant figure out how to do this problem?

Question

How do I factor this out I am stumped could it be prime please help.

U²-22U-48

Answer 1

Find two integers that multiply to equal -48, but add to equal -22, which are -24 and 2:

(u + 2)(u - 24) <===ANSWER

Answer 2

With a negative number, you know the factor will have one negative and one positive factor.

(U+2)(U-24)

Answer 3

-24 and +2

When in doubt, use the quadratic formula.

Answer 4

(u-24)(u+2)=0

u=24

u=-2

Answer 5

just use the quadratic formula if you're stuck.

given Ax^2 + Bx + C

x=(-b+-sqrt(b^2-4ac))/2a

Answer 6

If (u + b)(u + d) = u^2 + u(b + d) + bd = u^2 - 22u - 48, then you're looking for two numbers (b and d) which sum to -22 and product is -48. From the latter, one will be positive and the other will be negative. Given a difference of 22 units, we have either 2 and -24 or -24 and 2. Since we're looking for -22, it must be -24 and 2, so we have our factors (u - 24) and (u + 2). We can go ahead and multiply them to check if we made an undetected mistake somewhere in our reasoning.