Question:

Values of t? Calc help?

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Find all the values of t in the interval [0,2π] if tan t-3 cot t=0.

Not sure what the steps are. Can someone please help! :]

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3 ANSWERS


  1. what is the punctuation between the tan and the cot?


  2. tant-3cot t=0

    sin(t)/cos(t) = 3 *cos(t)/sin(t)

    sin(t) ^2 = 3 cos(t)^2

    tan(t) ^2= 1/3

    tan(t) = 1/sqr(3)

    get t

  3. tan t - 3/tan t = 0

    tan^2 t -3 = 0

    tan^2 t = 3

    tan t = +/- sqrt(3)

    t = pi/3, 2pi/3, 4pi/3, 5pi/3

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