Volume is y^3 - 13y^2 +54 y -72cm and width is y-6cm what is the length and height? please show the work-up.?

Question

Help!!!

Answer 1

This does not make sense - the volume expression must have been mis-stated, there's something missing here and a "solution" cannot be determined!!!

Answer 2

assuming you mean a Quader

V= w*l*h

otherwise for a piramide

V= 1/3 * w * l * h

so V divided by w

| 1 | -13 | 54 | -72 |

| 0 |  6  | -42 | 72 |

| 1 |  -7 |  12 |  0  |

y² - 13y + 12  is length * height

we can`t say what exactly each one is

but y² - 13y + 12 = (y-12)(y-1)

some possible solution are



L=y-12 and H= y-1

L=y-1 and H = y-12

L=1 and H=y² - 13y + 12

L=y² - 13y + 12 and H =1

.....