Question:

Volume occupied by 1.5 moles of CH4 at STP is what?

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a. 44.8 L

b. 33.6 L

c. 22.4 L

d. 11.2 L

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  1. The ideal gas equation can be used to solve this problem. The condition is in STP which means that the temperature is 0deg Celcius or 273.15K and pressure is 1atmosphere.

    molar mass of CH4 (methane) = 16.05g/mol

    moles of CH4 (n) = 1.5 mol

    R = 0.0821 L-atm / mol-K

    T = 273.15K

    P = 1atm

    PV = nRT

    V = nRT / P

    Volume = (1.5 mol x 0.0821 L-atm/mol-K x 273.15 K) / 1 atm

    Volume = 33.6 L

    The answer is:

    B. 33.6 L


  2. Volume of one mole (assuming ideal gas law) at STP = 22.4 L

    1.5 mol = 22.4*1.5 = 33.6 L
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