WEIRD MIDPOINT QUESTION HELP?

Question

Find the midpoint of A if B(0.5,5) is the midpoint of line AC and C has coordinates (-3,6)

Answer 1

Do you mean, find the POINT, A?

Let A = (x, y).  Then the mid point of AC is, using the midpoint formula:

( (-3+x)/2, (6+y)/2 )

This should be equal to B = (0.5, 5).  So:

(-3+x)/2 = 0.5

(6+y)/2 = 5

Solve the first equation for x and the second for y.

Answer 2

i think you mean find COORDINATES OF A..lol

The mid point of A would be (-3+X)/2 and , (6+Y)/2

so A(4,4) :D

                                      

Answer 3

The x coordinate of the midpoint is the average of the x values of the endpoint. Therefore, if x is the unknown x coordinate of point A

0.5 = (x + -3)/2

Multiply both sides by 2

1 = x + -3

add 3 to both sides

4 = x

If y is the unknown y coordinate of the point A

5 = (y + 6)/2

Multiply both sides by 2

10 = y + 6

subtract 6 from both sides

10 - 6 = y + 6 - 6

4 = y

Answer 4

B(0.5,5)

C(-3,6)

A(??)

the line ABC:

(y-5)/(6-5)=(x-1/2)/(-3-1/2)

y-5= -2/7x + 1/7

y= -2/7x + 36/7

the distans IABI = IBCI

Ixb-xcI=Ixa-xbI

I0.5+3I=Ixa-0.5I

3.5=xa-0.5

xa=4

ya= -2/7*4+36/7

ya=-8/7+36/7=28/7=4

A(4;4)

Answer 5

Are you trying to cheat on your hw? thats not gonna get you anywhere....