Question:

WHAT IS JUST THE INVARIANT FOR THIS? 10 POINTS!! math :)?

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Determine the inverse functions for the functions below. Begin by switching varaiables in the original function, then solving for the 'new' y. For each case sketch the function and its inverse.

Have no idea what this is or what to do. Please explain how u found answer. 10 Points! :)

3. y= (2/3)x - 4

What is the inverse fuction for this and what in the invariant?

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  1. Find the inverse: take x= (2/3)y - 4

    and solve for y.

    (2/3)y = x + 4

    y = (3/2)x + 6

    (Can't help you with the 'invariant' . . . I haven't studied this stuff for a long time)


  2. exchange the variables and solve for y

    x= (2/3)y - 4

    (2/3)y = x + 4

    y = (3/2)x + 6

    is the invariant the degree of the polynomial? in this case it is 1.

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