Wat is th answer for this address....SUBNETTING?

Question

wat wil be th subnet mask and no of subnets and valid hosts.

10.40.12.25/16 and 10.40.12.28/26.

Answer 1

well...a /16 cidr is 255.255.0.0.  Since each octet can take at most 256.  To get the /16 just do 256x256 - 2 for hosts. so /16 is 65,536 total IP's  and 65,534 hosts total.  For /26....since /24 is 255.255.255.0 then /26 is 255.255.255.192.  Now we know that /24 takes a total of 256 IP's and 254 host IP's...to get /26 custom CIDR the table would go 256,128,64,32,16,8,4,2,1 as the octet goes up in the sequence of 0,128,192,224,240,248,252,254,255.  So /26 would have 64 total IP's and 62 hosts.  You can make a real easy table with those numbers i just put and memorize it.  That will help with these picky subnet questions.

A great site i used to use for subnetting was http://www.learntosubnet.com/.  Go over those lessons and you'll be a pro!

Good luck

Answer 2

255.255.0.0  - 65534 hosts

255.255.255.192 - 62 hosts