Question:

We are trying to solve for AE. With the problem AE^2+BE^2=AE^2?

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we are trying to find AE

BE=12

AE=13

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  1. Your question doesn't make perfect sense. We can solve the equation given for AE:

    AE^2 + BE^2 = AE^2

    Subtract AE^2 from both sides:

    BE^2 = 0

    From that, we can gather that AE can be any number at all, and BE must be 0. However, from the additional details in your question, I'm thinking you made a typo. What I suspect you meant to say was:

    AB^2 + BE^2 = AE^2

    Basically, I guess you have a right-angled triangle with a known hypotenuse and another side, and you want to find the other side?

    AB^2 + 12^2 = 13^2

    AB^2 + 144 = 169

    AB^2 = 25

    AB = 5 (ignore any negative solutions, since a side length is always positive)


  2. BE^2 has to be equal to zero, or the equation is inaccurate.   But that means AE can be equal to anything, right?

    And your BE=12 AE=13 details don't make any sense to me at all.

    <edit>Very good speculation "alwbsok"  I think you answered the question that the asker was really trying to ask!

  3. ??

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